Class Summary 10/15/04
CHM 688
Mid-Term Examination
Monday,
10/25/04 IN CLASS
10/15 Hückel Treatment for Larger Systems
“Frost Mnemonics” get energy levels for n-annulenes
Ej = a + mjb mj = 2 cos(2pj/n)
Even n j = 0, ±1, ±2, …, ±n/2
Odd n j = 0, ±1, ±2, …, ±(n-1)/2
For acyclic systems mj = 2 cos(pj/n+1)
Classification of Hydrocarbons (Alternate/Non-alternate hydrocarbons (star/non-star)
Alternate hydrocarbons have MO’s symmetrically distributed about a
Even Alternate Hydrocarbons (EAH) have same # above and below
Odd Alternate Hydrocarbons (OAH) have sane # above and below, and one on a
Non-Alternate Hydrocarbons do NOT have symmetric MO arrangements
Electron Density
In neutral Alternate Hydrocarbons, each carbon has a total of 1 e-.
Charge in OAH is NOT evenly distributed, but reflects the properties of the NBMO
Sum of coefficients around a node = ZERO
Using the star/non-stars, one get easily get the coefficients and charges of the NBMO.
References
Mentioned
Frost, A.A., Musulin, B. Mnemonic device for molecular-orbital energies J. Chem. Phys. (1953), 21, 572-3.
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