Two important important parameters that can be determined from a cell potential are the equilibrium constant for the cell reaction and the free energy change for the cell reaction.
To calculate the equilibrium constant for an electrochemical cell we need to know:
At equilibrium Q = K. Substituting in K for Q, and the values for R, T, and F, we get:
Example: Find the value of the equilibrium constant at 25oC for the cell reaction for the following electrochemical cell:
Cu | Cu2+(1 M) || Ag+(1 M) | Ag.
2 Ag+(aq) + 2 e- 2 Ag(s) | Eoreduction = + 0.799 V |
Cu(s) Cu2+(aq) + 2 e- | Eooxidation = - 0.518 V |
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2 Ag+(aq) + Al(s) 2 Ag(s) + Cu2+(aq) | Eocell = + 0.281 V |
n = 2 moles of electrons
Note: values for the equilibrium constant for electrochemical cell reactions are sometimes very large.
Determining the Standard State Free Energy Change from Eocell
To determine the standard state free energy change for a cell reaction
DGo
= standard state free energy change (joules)
n = number of moles of electrons
transferred
F = Faraday's constant (96,485
C/mol e-)
Eocell
= standard state cell potential (volts or joules/C)
Example: Find the value of the equilibrium constant at 25oC for the cell reaction for the following electrochemical cell:
Cu | Cu2+(1 M) || Ag+(1 M) | Ag.
(The solution for the determination of the Eocell and the number of moles of electrons, n, are shown in the example in the previous section. Click HERE to see the solution.)
Determining the Non-Standard State Free Energy Change
To determine the non-standard state free energy change:
Example: Calculate the free energy change for the following electrochemical cell.
Zn(s) | Zn2+ (1.50 M) || Cu2+ (0.25 M) | Cu(s)
Zn(s) Zn2+(aq) + 2 e- | Eooxidiation = + 0.762 volts |
Cu2+(aq) + 2 e- Cu(s) | Eoreduction = + 0.339 volts |
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Zn(s) + Cu2+(aq) Zn2+(aq) + Cu(s) | Eocell = + 1.101 volts |